(2x+3)^2-(x=6)(x-5)

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Solution for (2x+3)^2-(x=6)(x-5) equation: 



(2x+3)^2-(x=6)(x-5)

We move all terms to the left:

(2x+3)^2-(x-(6)(x-5))=0



We calculate terms in parentheses: -(x-6(x-5)), so:

x-6(x-5)

We multiply parentheses

x-6x+30

We add all the numbers together, and all the variables

-5x+30

Back to the equation:

-(-5x+30)



We get rid of parentheses

(2x+3)^2+5x-30=0

We add all the numbers together, and all the variables

5x+(2x+3)^2-30=0

We move all terms containing x to the left, all other terms to the right

5x+(2x+3)^2=30

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